Find Max. and Next Max.

Input	An array of numbers
Output	Max  and next max
Complexity O(n)

1 Maximum(Array A)
2 Set n=number of element in array;
3 Compare first two numbers
4 If Array[first] is greater then set first= max and second=nextmax
5 otherwise set first=nextmax and second=max;
6 for i=2 to n do
7   if Array[i] > max
8       store max in temp;
9       assign Array[i] to max;
10      if temp > nextmax
11         assign temp to nextmax;
12  else
13        if array[i] > nextmax
14        assign array[i] to nextmax;			
15  Print max and nextmax;

/** Code Written By: Ankit Babbar
    Date: 26 March,2011
    Quesn: Running on safe path
**/
#include<stdio.h>
#include<conio.h>
int main()
{
	int a[50],num,max,nmax,t,i;
	clrscr();
	printf("how many numbers you want to enter ");
	scanf("%d",&num);
	printf("enter the no.");
	for(i=0;i<num;i++)
            scanf("%d",&a[i]);
	if(a[0]>a[1])
	{
		max=a[0];
		nmax=a[1];
	}
	else
	{
		max=a[1];
		nmax=a[0];
	}
	for(i=2;i<num;i++)
	{
		if(a[i]>max)
		{
			t=max;
			max=a[i];
			if(t>nmax)
			nmax=t;
		}
		else if(a[i]>nmax)
		nmax=a[i];
	}

	printf("Max no is %d  and next  max no is %d  :  ",max,nmax);
	return 0;
}