Even and Odd
Algorithm
Input An integer. Output Print number is even or odd. Complexity O(1) Even-odd(n) 1 If (n%2=0) then 2 Print number is even 3 else 4 Print number is odd
Algorithm Description
Even-odd() function takes an integer and checks whether n is divisible by 2 or not.if its remainder is0 then number is even otherwise number is odd.
C Code
//To check wheather a number is even or odd
//Input : Any integer number
#include< stdio.h>
#include< conio.h>
int main()
{
int num;
printf("Enter a number ");
scanf("%d",&num);
if(num%2==0)
printf("Number %d is Even",num);
else
printf("Number %d is Odd",num);
}
